The NFL season is in full swing and Week 7 was an exciting one for fans. One of the biggest stars of the week was Tennessee Titans wide receiver AJ Brown, who had a breakout performance. Brown had nine receptions for 134 yards and two touchdowns in the Titans’ victory over the Los Angeles Chargers. His performance earned him the title of NFL Offensive Player of the Week.
Brown has been a key contributor to the Titans’ success this season. He has been a reliable target for quarterback Ryan Tannehill, catching 34 passes for 544 yards and four touchdowns. Brown’s ability to make plays down the field has been a major factor in the Titans’ offensive success. He is averaging 16 yards per reception, which is the highest among all NFL receivers with at least 30 receptions.
Brown’s performance against the Chargers was especially impressive. He was able to make plays in traffic and showed off his impressive speed and agility. His two touchdowns were highlight-reel plays that showcased his ability to make plays in the open field. Brown also showed off his physicality, as he was able to fight off defenders and make contested catches.
Brown’s performance against the Chargers was just the latest in a string of impressive performances this season. He has been a key part of the Titans’ offense and has been a reliable target for Tannehill. Brown has also been a leader in the locker room, setting an example for his teammates with his work ethic and dedication.
Brown’s performance in Week 7 was an impressive one, and it is clear that he is one of the top players in the NFL right now. He has been a major factor in the Titans’ success this season and is showing no signs of slowing down. With Brown leading the way, the Titans look poised to make a deep run in the playoffs this season.